SOLUTION: find the domain #1 g(x)=x+8/X^2+9X #2 f(x)=9x/square root of x+4

Algebra.Com
Question 696402: find the domain
#1 g(x)=x+8/X^2+9X
#2 f(x)=9x/square root of x+4

Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
find the domain
#1 g(x)= (x+8)/(X^2+9X)
Factor:
g(x) = (x+8)/[x(x+9)]
The denominator cannot be zero.
Domain: All Real Numbers except x = 0 and x = -9
=====================================================
#2 f(x)= (9x)/sqrt(x+4)
---
The denominator must be positive.
Domain: All Real numbers greater than -4.
===================
Cheers,
Stan H.
===================

RELATED QUESTIONS

find domain of (fg)(x) when f(x)=square root of 6x+2 ang g(x)=square root of... (answered by varun)
perform the request operation or operations. find the domain of each. f(x)= square root... (answered by rapaljer)
f(x)=x^2+9x and... (answered by ikleyn)
Find the domain of the function:... (answered by braceface10)
Can you help me? Am I on the right track? f(x) = 3x+1 g(x) = (x^2 + 5x)^-1/2 find... (answered by MRperkins)
find the domain of the function. f(x)= ln(x^2-9 /... (answered by ikleyn)
if f(x)=1/x & g(x)=square root of x+2, find... (answered by stanbon)
f(x) = x x+2 , g(x) = x x−1 Find the domain of f... (answered by josgarithmetic)
Let f(x) =x^2+9x and g(x)=1-x Find (f/g)(x) and... (answered by MathLover1)