SOLUTION: how do i do Given the function, (1/3X) + 3/4 = Y, what is Y when X = 1?

Question 693436: how do i do Given the function, (1/3X) + 3/4 = Y, what is Y when X = 1?
Found 2 solutions by RedemptiveMath, MathLover1:
Answer by RedemptiveMath(80) (Show Source): You can put this solution on YOUR website!
All we need to do is put 1 wherever we find x in the equation. Once we "plug" 1 in for x, we solve using order of operations. So,

(1/3X) + 3/4 = Y (writing your equation)
(1/3)(1) + 3/4 = Y (I'm assuming that 3 in 1/3 and x are being multiplied?)
1/3 + 3/4 = Y (multiplication before addition)
4/12 + 9/12 = Y (find common denominators before adding fractions)
13/12 = Y (add)
1 1/12 = Y (rewrite improper fraction as mixed number).

It depends on your teacher whether you keep the fraction improper or write it as a mixed number. You can now say that when x is 1, y is 1 and 1/12 or 13/12.

Answer by MathLover1(20850) (Show Source): You can put this solution on YOUR website!
if you have this:
, what is when
plug in

but, if you have this:
, what is when
plug in

as you can see, in both cases the solution happens to be same

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