SOLUTION: difference of quotient {{{ f(y)= -4y^2+6y }}} {{{ f(1+h)-f(1) }}} h not = 0

SOLUTION: difference of quotient {{{ f(y)= -4y^2+6y }}} {{{ f(1+h)-f(1) }}} h not = 0

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Question 663856: difference of quotient h not = 0
Answer by kevwill(135) (Show Source): You can put this solution on YOUR website!

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