SOLUTION: find the intercepts and vertex y=-x^2-4x find intercepst x^3-2x^2-9x=18=0

SOLUTION: find the intercepts and vertex y=-x^2-4x find intercepst x^3-2x^2-9x=18=0

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Question 65282: find the intercepts and vertex
y=-x^2-4x
find intercepst
x^3-2x^2-9x=18=0
Answer by amran(4) (Show Source): You can put this solution on YOUR website!
find the intercepts and vertex for
When x=0, y=0.
When y=0,

x = 0 or x = -4.
Hence the intercept points are (0,0) and (-4,0)

Hence the vertex is (-2,4)

find intercept for x^3-2x^2-9x=18=0

x = 2 , 3 or -3
Hence the intercepts are (2,0) , (3,0) and (-3,0)

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