y=(1/5)x+1 The range is {-2, 3, 6}, Substitute y=-2 in y=(1/5)x+1 -2=(1/5)x+1 Multiply both sides by 5 to clear of fractions: -10=x+5 -15=x So -15 is in the domain. This rules out A and C Substitute y=3 in y=(1/5)x+1 3=(1/5)x+1 Multiply both sides by 5 to clear of fractions: 15=x+5 10=x so 10 must be in the domain, so it's still either B or D Substitute y=6 in y=(1/5)x+1 6=(1/5)x+1 Multiply both sides by 5 to clear of fractions: 30=x+5 25=x So 25 must be in the domain. Answer: D. {-15, 10, 25} Edwin