# SOLUTION: I don't get how to solve funtions. I get lost quickly. Any help out there? Given f(x)=5x^2/x-2 Evaluate f(-1) Evaluate f(3) State the domain of function f(x) thanks!

Algebra ->  Algebra  -> Functions -> SOLUTION: I don't get how to solve funtions. I get lost quickly. Any help out there? Given f(x)=5x^2/x-2 Evaluate f(-1) Evaluate f(3) State the domain of function f(x) thanks!      Log On

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 Algebra: Functions, Domain, NOT graphing Solvers Lessons Answers archive Quiz In Depth

 Question 64444: I don't get how to solve funtions. I get lost quickly. Any help out there? Given f(x)=5x^2/x-2 Evaluate f(-1) Evaluate f(3) State the domain of function f(x) thanks!Found 2 solutions by stanbon, josmiceli:Answer by stanbon(57372)   (Show Source): You can put this solution on YOUR website!Given f(x)=5x^2/(x-2) Evaluate f(-1)=4(-1)^2/(-1-2)=4*1/(-3)=-(4/3) Evaluate f(3)=5(3)^2/(3-2)=5*9/1=45 State the domain of function f(x) When finding a domain it is easier to determine vales x CANNOT take. In your function x CNNOT be 2 because that would make the denominator zero, which would make the fraction meaningless. That is the only value x CANNOT take. So, the domain is all real number EXCEPT x=2. Cheers, Stan H. Answer by josmiceli(9686)   (Show Source): You can put this solution on YOUR website! f(-1) = ? Just substitute -1 for x everywhere you see x in the function f(3) = ? If you do the long division, you get As x grows positively, the 1st term gets more positive and the last term approaches zero. As x grows negatively, the 1st term gets more negative, and the last term still approaches zero. When x = +2, the last term becomes +infinity. So, the domain of this is +2 < x < +2