Question 644120: Find an equation of the line tangent to the circle (x−3)2+(y−3)2=25
at the point (6,7). Found 2 solutions by reviewermath, MathLover1:Answer by reviewermath(1029) (Show Source): You can put this solution on YOUR website! The center of the circle is (h,k).
Therefore the center of is (3,3).
The tangent line is perpendicular to the segment joining (6,7) and (3,3).
slope of the segment joining (6,7) and (3,3) = .
negative reciprocal of 4/3 = -3/4
Equation of tangent line:
Answer: .
Here's the graph: Answer by MathLover1(20850) (Show Source): You can put this solution on YOUR website! given:
the circle
and the point (,)
A circle with center (a,b) and radius r has equation
(x - a)^2 + (y - b)^2 = r^2
Your circle has equation
(x - 3)^2 + (y - 3)^2 = 25
and hence and . Thus your circle has (center (3,3) and radius .
a plot of the circle
at the point (,)=(,)
the tangent to a circle at the point (x,y) is:
at the point (,)
..........equation of the line tangent to the circle
follow this link and you will see image of your circle and tangent:
http://imageshack.us/photo/my-images/407/capture831201285126pm.jpg/