SOLUTION: I am trying to find out what f/g is for f(x)= x^2-2x-24 and g(x)=x^2-x-30. I know that you must divide them and I successfully completed the other parts to this problem which was f

Question 638400: I am trying to find out what f/g is for f(x)= x^2-2x-24 and g(x)=x^2-x-30. I know that you must divide them and I successfully completed the other parts to this problem which was finding f+g, f-g, and f*g. I just can't remember how to divide equations with variables in them. This is the problem that needs to be solved. x^2-2x-24/x^2-x-30. Also I need to specify the domain. Thank you
Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
f/g is for f(x)= x^2-2x-24 and g(x)=x^2-x-30
.
f/g:
[x^2-2x-24]/[x^2-x-30]
factor both:
[(x-6)(x+4)]/[(x-6)(x+5)] Note: this is where you can determine domain
canceling:
(x+4)/(x+5) (this is f/g)
.
Domain specifies what values x can take (we just have to avoid when the denominator becomes zero).
The denominator becomes zero when x=6 OR x=-5
domain is therefore:
(-oo, -5) U (-5,6) U (6,+oo)
where oo stands for infinity

RELATED QUESTIONS
Given that f(x) = 1/x and (f/g)(x) = (x + 1)/(x^2 - x), find the function g. Let me (answered by math_tutor2020)

Hi, my name is michelle. im working on a midterm review that i have tomorrow at 12. im... (answered by ad_alta)

Hello, I have been trying for hours to help my son with his Algebra I homework and I am... (answered by ReadingBoosters,MathTherapy)

Let f(x) =2x^2+3 and g(x) = 4x-8. Find each composition. (fog)(x) f(g(x)) =... (answered by Alan3354)

I kind of understand how to do these f◦g and g◦f problems, but I dont know... (answered by stanbon)

1.3 What is f o g if: f(x) = -2x+7 and g(x)=x+2 Thank you for your assistance, I am... (answered by oscargut)

Hello I'm having a problem with one of my question on operations on functions. I will... (answered by Fombitz)

I am trying to find two different functions so that... (answered by vleith)

composite function(FoG)(x)= F(x)=x^2-2x+1 G(x)= sqrt x-2 I know you (answered by Fombitz)