Hi,

y+5=2(x+2)^2  (y = 0 ⇒  (x+2)^2 = 5/2 and x-intercepts are: -2 ± 

y  =2(x+2)^2 - 5 ,              V(-2,-5)

the vertex form of a Parabola opening up(a>0) or down(a<0)is:  

where is the vertex  and  x = h  is the Line of Symmetry



 

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