SOLUTION: A bus leaves a station at 1 P.M., traveling west at an average
rate of 44 mi/h. One hour later a second bus leaves the same station, traveling
east at a rate of 48 mi/h. At what
Algebra.Com
Question 63351: A bus leaves a station at 1 P.M., traveling west at an average
rate of 44 mi/h. One hour later a second bus leaves the same station, traveling
east at a rate of 48 mi/h. At what time will the two buses be 274 mi apart?
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
44X+48(X-1)=274
44X+48X-48=274
92X=274+48
92X=322
X=322/92
X=3.5 HOURS AFTER THE FIRST BUS LEAVES THEY WILL BE 274 MILES APART OR @ 4:30PM.
RELATED QUESTIONS
could you help to solve this problem and show in a equation please help
A bus leaves a (answered by tutor_paul)
A bus leaves a station at 1 P.M., traveling west at an average rate of 44 mi/h. One hour... (answered by Nate)
A bus leaves a station at 1 p.m., traveling west at an average rate of 44 mi/h. One hour (answered by checkley71,stanbon,Nate)
Can someone help me on this problem?
A bus leaves a station at 1 P.M., traveling... (answered by venugopalramana,jenrobrody)
A bus leaves a station at 1 P.M., traveling west at an average rate of 44 mi/h. One hour... (answered by venugopalramana)
A bus leaves a station at 1 P.M., traveling west at an average
rate of 44 mi/h. One hour (answered by checkley71,josmiceli)
how do i work this out??
A bus leaves a station at 1 P.M., traveling west at an average
(answered by checkley71)
A bus leaves a station at 1 P.M., traveling west at an average
rate of 44 mi/h. One hour (answered by checkley75)
A bus leaves a station at 1 P.M., traveling west at an average
rate of 44 mi/h. One hour (answered by checkley75)