SOLUTION: Hello I am working on even, odd, or neither functions. I have been doing great on most of them until I hit one that i really do not get. My question: is log(x^2/y) even, odd, or

Question 629996: Hello I am working on even, odd, or neither functions. I have been doing great on most of them until I hit one that i really do not get.
My question: is log(x^2/y) even, odd, or neither?
i know that when log(x/y) it is the same as logx-logy. I tried separating it like that, and then changing the sign. so my problem was like :
log(x^2/y)= logx^2-logy
f(x)=logx^2-logy
f(-x)=-logx^2+logy
this function is odd.
I do not know if i am doing it right, I would just want to know how to do it. Thanks
Answer by jsmallt9(3758) (Show Source): You can put this solution on YOUR website!
A function is "even" if f(-x) = f(x) for all x's in the domain.
A function is "odd" if f(-x) = -f(x) for all x's in the domain.
A function is "neither" if it is not even or odd.

Logarithms are perhaps the ultimate "neither". If log(x) exists, log(-x) does not even exist since arguments of logs can only be positive!

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