SOLUTION: Find the domain
y=√60x-25x^2-36
Please note that the square root sign cover not just 60x but 60x-25^2-36.
y=√5x^2+6x+1+1/3x+5
Please note again that the s
Algebra.Com
Question 629043: Find the domain
y=√60x-25x^2-36
Please note that the square root sign cover not just 60x but 60x-25^2-36.
y=√5x^2+6x+1+1/3x+5
Please note again that the square root sign cover 5x^2+6x+1.
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
The domain of a function is the set of all values of the independent variable for which the function exists.
The square root function exists mapped to the real numbers for all values of the independent variable for which the radicand is greater than or equal to zero.
Set up the inequality:
I'll leave it as an exercise for you to demonstrate that there is exactly one value of 
for which this inequality is true, and hence the domain consists of this single value.
On the other hand, if you map the function to the complex numbers, then the domain is all reals, thus:
\ =\ \sqrt{60x\ -\ 25x^2\ -\ 36}\right)\ =\ \left{x\ \in\ \mathbb{R}\right})
John
My calculator said it, I believe it, that settles it
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