SOLUTION: If the inventor in Exercise 53 charges $4 per unit, then her profit for producing and selling x units is given by the function:
P(x) = 2.25x – 7000
a. What is her profit if
Algebra.Com
Question 62735: If the inventor in Exercise 53 charges $4 per unit, then her profit for producing and selling x units is given by the function:
P(x) = 2.25x – 7000
a. What is her profit if she sells 2000 units?
b. What is her profit if she sells 5000 units?
c. What is the break-even point for sales?
Answer by 303795(602) (Show Source): You can put this solution on YOUR website!
Substitute x= 2000 and x=5000 into the profit equation to solve the first two.
Part a)P(x) = 2.25*2000 – 7000 = -$2500 ie a loss of $2500
Part b)P(x) = 2.25*5000 – 7000 = $4250
Part c) The break even point has a profit of 0.
0 = 2.25*x – 7000 Add 7000 to each side
7000 = 2.25*x – 7000 + 7000
7000 = 2.25*x Divide each side by 2.25
x = 3111 Units
(Actually 3111 units makes a 25 cent loss and 3112 units makes a $2 profit)
RELATED QUESTIONS
Business and finance. If the inventor in exercise 53 charges $4 per unit, then her profit (answered by venugopalramana)
Solve the following applications involving functions.
If the inventor in... (answered by JP)
I need help with these problems please.
53. Business and finance. The inventor of a... (answered by stanbon)
If the inventor in exercise 53(see below) charges $4 per unit,then her profit for... (answered by Hook)
Business and Finance. If the inventor in exercise 53 charges $4 per unit, then her profit (answered by Poohbear272)
Business and Finance. If the inventor in exercise 53 charges $4 per unit, then her profit (answered by Poohbear272)
Solve the following applications involving functions.
10. Business and finance. If... (answered by jim_thompson5910)
Business and finance. If the inventor in exercise 53 charges $4 per unit, then her... (answered by tutorcecilia)
I would like to ask a business and finance applcation involving functions.
The inventor... (answered by scott8148)