SOLUTION: If h(x)= x^2-4xy+y^2/(x+2)(y-3), find f(-1,2)

Question 625577: If h(x)= x^2-4xy+y^2/(x+2)(y-3), find f(-1,2)
Answer by oscargut(2103) (Show Source): You can put this solution on YOUR website!
If f(x,y)= x^2-4xy+y^2/(x+2)(y-3), find f(-1,2)
f(-1,2)= [(-1)^2-4(-1)(2)+2^2]/(-1+2)(2-3)
= (1+8+4)/(-1) = -13
Answer: -13
If you have any doubt or if you have more problems my e-mail is:
mthman@gmail.com
RELATED QUESTIONS
4x + y = 3 1/2 x2 - 4xy = 3 Find x and... (answered by greenestamps)

4xy/x^2-y^2 +... (answered by Alan3354)

4xy/x^2-y^2 +... (answered by drk)

x=1,y=-2... (answered by mukhopadhyay)

for x=1, y=-2 3x^2y-4xy^2+xy (answered by mukhopadhyay)

Factorise: x^2 - 2x + 4xy + 4(y^2) - 4y -... (answered by vleith)

The function f(n) is defined for all integers n, such that f(x) + f(y) = f(x + y) -... (answered by CPhill,ikleyn)

8x^2 /x^-2 y^2 * (4xy^2)^-1 /x^2... (answered by MathLover1)

Simplify {{{ (((8x^2)(y^2))/(x^-2)(y^2)))}}}* {{{((4xy^2)^-1)/(x^2y) }}} (4xy^2)^-1 is... (answered by Alan3354)