# SOLUTION: I have to solve this algebraically, not by using a graph: A parabola has a vertex (8, 3) and one x intercept of 5. Determine the coordinates of the other x- intercept.

Algebra ->  Algebra  -> Functions -> SOLUTION: I have to solve this algebraically, not by using a graph: A parabola has a vertex (8, 3) and one x intercept of 5. Determine the coordinates of the other x- intercept.       Log On

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 Algebra: Functions, Domain, NOT graphing Solvers Lessons Answers archive Quiz In Depth

 Click here to see ALL problems on Functions Question 622355: I have to solve this algebraically, not by using a graph: A parabola has a vertex (8, 3) and one x intercept of 5. Determine the coordinates of the other x- intercept. Answer by ewatrrr(10682)   (Show Source): You can put this solution on YOUR website! ``` Hi, solving algebraically: Parabola with V(8,3) and passing thru (5,0) y = a(x -8)^2 + 3 0 = a(5-8)^2 + 3 -3/9 = a y = (-1/3)(x-8)^2 + 3 0 = (-1/3)(x-8)^2 + 3 -3 = (-1/3)(x-8)^2 (x-8)^2 = 9 (x-8) = ± 3 x = 5 and x = 11 (11,0) are the coordinates of the other x- intercept. ```