SOLUTION: (a) Find dy/dx for {{{ xy^4+sqrt(2x+3y)= 6 }}}
(b) Show that the point (x,y)= (3,1) lies on the curve defined by the equation in part (a), and find the slope of the tangent line
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Question 592647:  (a) Find dy/dx for 
(b) Show that the point (x,y)= (3,1) lies on the curve defined by the equation in part (a), and find the slope of the tangent line at this point. 
Answer by richard1234(7193)   (Show Source): You can put this solution on YOUR website!
 Take derivative of both sides with respect to x (note that since y is a function of x, you have to use the chain rule).
Solve algebraically for dy/dx.
For part b, it is easy to show that (3,1) is on the curve because if you replace x=3, y=1 into the equation you should get a true statement. To find dy/dx at (3,1), replace x=3, y=1 into your expression for dy/dx (which you will have found in part a). 
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