# SOLUTION: Please Find the Derivatives of the following and simplify: y=5e^3x y=1/e^x y=e^3 y=e^x2e^2x Thanks!

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 Click here to see ALL problems on Functions Question 59236: Please Find the Derivatives of the following and simplify: y=5e^3x y=1/e^x y=e^3 y=e^x2e^2x Thanks! Found 2 solutions by venugopalramana, funmath:Answer by venugopalramana(3286)   (Show Source): You can put this solution on YOUR website!Please Find the Derivatives of the following and simplify: y=5e^3x DY/DX = 5*3E^3X=15E^3X y=1/e^x=E^(-X) DY/DX = -1E^(-X)=-1/E^X y=e^3 =CONSTANT DY/DX =0 y=e^x2e^2x DO YOU MEAN Y=[E^X][2E^2X]..IF SO DY/DX = (E^X)[2*2E^(2X)+2E^2X]= 6(E^X)(E^2X) ----IF YOU MEANT [E^(X^2)][E^2X]..THEN DY/DX = [E^(X^2)]2E^(2X)+[E^2X]2XE^(X^2)=2[E^(X^2)][E^2X][1+X) Thanks! Answer by funmath(2925)   (Show Source): You can put this solution on YOUR website!Find the Derivatives of the following and simplify: d/dx[cf(x)]=cf'(x) d/dx[e^x]=e^x d/dx[c]=0 The chain rule: d/dx[f(g(x)]=f'(g(x))g'(x) : Use the chain rule: : ---->> Use the chain rule again: : There is no x, this is a constant even though it doesn't look like one. . The derivative of a constant is 0. : I'm not sure if I'm interpretting you right on this one, let me know if there's a misunderstanding!!! -------->> --->> Use chain rule: : Happy Calculating!!!