SOLUTION: I am not sure if i submitted it to the correct help section, but here it goes... determine whether each relation is a function. x^2 = 1 + y^2

Question 58751This question is from textbook Elementary and Intermediate Algebra
: I am not sure if i submitted it to the correct help section, but here it goes...
determine whether each relation is a function.
x^2 = 1 + y^2 This question is from textbook Elementary and Intermediate Algebra

Answer by funmath(2933) (Show Source): You can put this solution on YOUR website!
I am not sure if i submitted it to the correct help section, but here it goes...
determine whether each relation is a function.
x^2 = 1 + y^2
****Anytime you have an absolute value of y or y raised to an even power it is NOT a function****
Watch what happens if we try to solve for y:

+/-
+/- The +/- means that there are two different possibilities for every x we put in, which is a no-no where functions are concerned.
Graphically you do not pass the vertical line test either:

I just remember ****, the rest is for general information, depending on what kind of proof you have to give your teacher.
Happy Calculating!!!
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