SOLUTION: x^2+4x+6 i need to find vertex

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Question 577888: x^2+4x+6 i need to find vertex
Answer by jim_thompson5910(28598) About Me  (Show Source):
You can put this solution on YOUR website!
In order to find the vertex, we first need to find the x-coordinate of the vertex.


To find the x-coordinate of the vertex, use this formula: x=%28-b%29%2F%282a%29.


x=%28-b%29%2F%282a%29 Start with the given formula.


From y=x%5E2%2B4x%2B6, we can see that a=1, b=4, and c=6.


x=%28-%284%29%29%2F%282%281%29%29 Plug in a=1 and b=4.


x=%28-4%29%2F%282%29 Multiply 2 and 1 to get 2.


x=-2 Divide.


So the x-coordinate of the vertex is x=-2. Note: this means that the axis of symmetry is also x=-2.


Now that we know the x-coordinate of the vertex, we can use it to find the y-coordinate of the vertex.


f%28x%29=x%5E2%2B4x%2B6 Start with the given equation.


f%28-2%29=%28-2%29%5E2%2B4%28-2%29%2B6 Plug in x=-2.


f%28-2%29=1%284%29%2B4%28-2%29%2B6 Square -2 to get 4.


f%28-2%29=4%2B4%28-2%29%2B6 Multiply 1 and 4 to get 4.


f%28-2%29=4-8%2B6 Multiply 4 and -2 to get -8.


f%28-2%29=2 Combine like terms.


So the y-coordinate of the vertex is y=2.


So the vertex is .