SOLUTION: I need help understanding how {{{ (x+1)^3(x-4)(x-0) }}} is equal to {{{ x^5-x^4-9x^3-11x^2-4x }}}
I've tried to figure out how that is the answer but the factor with the multipi
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Question 576349: I need help understanding how is equal to
I've tried to figure out how that is the answer but the factor with the multipilicty of 3 throws me off. Please help me, thank you!
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
^3\ =\ (x\ +\ 1)^2(x\ +\ 1)\ \cr.\cr =\ (x^2\ +\ 2x\ +\ 1)(x\ +\ 1)\ \cr.\cr =\ x^3\ +\ 2x^2\ +\ x\ +\ x^2\ +\ 2x\ +\ 1\ \cr.\cr =\ x^3\ +\ 3x^2\ +\ 3x\ +\ 1)
Is the ^3)
part. Then just multiply the result above by each of the other two factors. Note 
is just 
In general, the binomial expansion is:
^n\ =\ \sum_{k\,=\,0}^n\ \left(n\cr k\right)\,x^{n\,-\,k}y^k)
Where )
is the number of combinations of 
things taken 
at a time and is calculated by !})
John
My calculator said it, I believe it, that settles it
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