SOLUTION: This is a question on inverse functions. Let y=f(x)=5x^3+8 The question wants the answer in the form y= cube root a(x)+b. where a and b are coefficients. I have come up with

Algebra ->  Algebra  -> Functions -> SOLUTION: This is a question on inverse functions. Let y=f(x)=5x^3+8 The question wants the answer in the form y= cube root a(x)+b. where a and b are coefficients. I have come up with      Log On

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Question 56078: This is a question on inverse functions.
Let y=f(x)=5x^3+8
The question wants the answer in the form y= cube root a(x)+b. where a and b are coefficients. I have come up with 1/5 for coeffcient a and I am thinking -(8/5) for coefficient b, but it does not seem to work.
Answer by rapaljer(4551) About Me  (Show Source):
You can put this solution on YOUR website!
As I explained in the previous exercise, I interchange the x and y, and solve for y.
y = 5x^3 + 8

Step 1: Interchange the x and y:
x = 5y^3 + 8

Step 2: Solve for y:
x-8 = 5y^3
%28x-8%29%2F5+=+y%5E3

Take the cube root of each side:
root%283%2C+%28x-8%29%2F5%29+=+y
root%283%2C+%28x%2F5%29-%288%2F5%29%29+=+f%5E%28-1%29%28x%29+

This is what I got!! I think you are correct!! Why do you think it does not work???

R^2 at SCC