SOLUTION: Factor: 36x^2

SOLUTION: Factor: 36x^2 - 72 + 35

Question 55099This question is from textbook Algebra Structure and Method book 1
: Factor: 36x^2 - 72 + 35 This question is from textbook Algebra Structure and Method book 1

Found 3 solutions by stanbon, rchill, Earlsdon:
Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
Factor: 36x^2 - 72x + 35
I assumed there was an "x" missing in your post.
If that is correct:
36x^2-72x+35
=(6x-5)(6x-7)
Cheers,
Stan H.

Answer by rchill(405)   (Show Source): You can put this solution on YOUR website!
Because the last term is positive and the middle term is negative, we know we will have two factors in the form of (Ax-C)(Bx-D), where A*B=36, C*D=35, and AD+BC=72.

Using trial and error can be quite painful. Starting with 35, the only factors possible are 1 and 35, and 5 and 7. There are several sets of factors for 36: 1 and 36; 2 and 18; 3 and 13; 4 and 9; 6 and 6.

Let's try using 5 and 7 for the factors of 35, and 6 and 6 for 36: . That works! If it didn't, we would have to painstakingly go through the list to see which ones satisfy the condition from the first paragraph above.
Answer by Earlsdon(6294)   (Show Source): You can put this solution on YOUR website!
Factor:
(sic)
I think that you might have dropped an x somewhere along the line, n'est ce pas?
Factor:

The possibilities for the first term are:

For the last term, the possibilities are:

You can try different combinations, but in the end you should get:

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