SOLUTION: What's the domain of f(x)=x/(x^2+2x-3

Question 549306: What's the domain of f(x)=x/(x^2+2x-3
Found 2 solutions by mathie123, stanbon:
Answer by mathie123(224) (Show Source): You can put this solution on YOUR website!

Note that the numerator can be any value of x.... but whenever we are dealing with fractions, the denominator cannot be 0 (check out any number divided by 0 on your calculator if you do not believe me.... you will end up getting an error)
This means that
cannot be 0
Well when does ??

Since our a value is 1, we need two values that multiply to our c value (-3) and add to our b value (2). If you think about it you will see that 3 and -1 do the trick.
So

and
when x=-3 and x=1
This means x can be anything except -3 and 1.

Let me know if any of the steps I took you are not sure about:) Merry Christmas!

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
What's the domain of f(x)=x/(x^2+2x-3)
------
That denominator cannot be zero:
x^2+2x-3 = 0
(x+3)(x-1) = 0
x = -3 ; x = 1
--------------------
Domain is "All Real Numbers except x = -3 and x = 1.
=====================================================
Cheers,
Stan H.

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