SOLUTION: 8(4u - 1)-12u = 11(2u - 6)
Algebra.Com
Question 513211: 8(4u - 1)-12u = 11(2u - 6)
Answer by umail08(87) (Show Source): You can put this solution on YOUR website!
8(4u - 1)-12u = 11(2u - 6)
32u – 8 – 12u = 22u – 66
20u – 8 = 22u – 66
20u – 22u = -66 + 8
-2u = -58
u = 29
RELATED QUESTIONS
(answered by ikleyn,Alan3354,josgarithmetic)
8(4U-1) -12U= 11(2U-6)
WHICH VARIABLE WOULD YOU REMOVE FIRST. I AM UNSURE HOW TO SOLVE... (answered by antsinmypants)
{{{(2u^(-1) - w^(-1))/(4u^(-2) -... (answered by Edwin McCravy)
(4u^3+4u^2+2)+(6u^3-2u+8)
simplify the... (answered by stanbon)
How do I solve the equation: 2u^4-5u^3-12u^2+2u-8 divided by u-4... (answered by Cintchr)
4u^2 + v + 2uv + 2u
(answered by ikleyn)
1. n+7+y+2+z
2. [-12+(-18)]+3
3 h+6-(-4+h)
4. (-8)n+5+16n-11
5. 5(n+2)+2
(answered by rapaljer)
g(u)=(12u-8)^3/2
find... (answered by stanbon)
Express as a trinomial
(U+3)^2
(U-8)^2
(2u+5)^2
(1-4u)^2
(U+2v)^2... (answered by rothauserc)