SOLUTION: How would you find the range of a function on the given domain.
f(x)={{{sqrt(9-x^2)}}}, {{{-3<=x<=1}}}
Algebra.Com
Question 503576: How would you find the range of a function on the given domain.
f(x)=,
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
The square root function is a function which increases over its entire domain (ie going from left to right, the y values increase)
So the smallest possible value in the range will result when you plug in x = -3 (the smallest value in the domain)
So plug in x = -3,
So when x = -3, y = 0. So the smallest value in the range is 0.
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Similarly, the largest value in the range will result from the largest value in the domain, which is x = 1
So plug in x = 1,
So when x = -3, . So the largest value in the range is
So the range is or
This means that the range in interval notation is
If you need more help, feel free to email me at jim_thompson5910@hotmail.com
or you can visit my website here: http://www.freewebs.com/jimthompson5910/home.html
Thanks,
Jim
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