SOLUTION: Find the x-intercept for y=x^2+x-6

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Question 49058: Find the x-intercept for y=x^2+x-6
Answer by tutorcecilia(2152) About Me  (Show Source):
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y=x^2+x-6 [Use the quadratic formuala to solve]
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+ [Quadratic Formula]
.
x+=+%28-1+%2B-+sqrt%28+1%5E2-4%2A1%2A-6+%29%29%2F%282%2A1%29+ [Plug-in the values]
a=1
b=1
c=-6
.
x+=+%28-1+%2B-+sqrt%28+25+%29%29%2F%282%29+ [Simplify]
.
x+=+%28-1+%2B-+%285+%29%29%2F%282%29+
.
x+=+%28-1+%2B+%285+%29%29%2F%282%29+
x+=+%28%284%29%29%2F%282%29%29+
x = 2
.
x+=+%28-1+-+%285+%29%29%2F%282%29+
x+=+%28%28-6+%29%29%2F%282%29%29+
x=-3
So, x = 2 or x = -3