SOLUTION: Given the function {{{ f(x)=2x^2+3x-5 }}} evaluate f(3). I did:
{{{ f(x)=2(3)^2+3 }}}
=54+3
=57
so f(x)=57? Did I do that right?
Algebra.Com
Question 477133: Given the function evaluate f(3). I did:
=54+3
=57
so f(x)=57? Did I do that right?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
f(x) = 2x^2+3x-5 evaluate f(3)
----------
f(3) = 2*3^2 + 3*3 - 5
---
f(3) = 18 + 9 - 4
---
f(3) = 23
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Cheers,
Stan H.
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