SOLUTION: Given f(x) x^2-4x-21, find the vertex and the x-intercept(s)
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Algebra: Functions, Domain, NOT graphing
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Question 47573
:
Given f(x) x^2-4x-21, find the vertex and the x-intercept(s)
Answer by
Nate(3500)
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f(x) = x^2 - 4x - 21
V(-b/2a,f(x))
V(2,-25)
x-intercepts:
0 = x^2 - 4x - 21
0 = (x - 7)(x + 3)
x - 7 = 0
x = 7
(7,0)
and
x + 3 = 0
x = -3
(-3,0)
(