SOLUTION: Find the maximum or minimum value of the function
f(t)= 10t^2 + 40t + 113
t = -40/(2*10) = -40/20 = -2 minimum
10(t^2 + 4t) + 113
10(t^2 + 4t +4) + 113 - 40
10(t + 2)^2
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-> SOLUTION: Find the maximum or minimum value of the function
f(t)= 10t^2 + 40t + 113
t = -40/(2*10) = -40/20 = -2 minimum
10(t^2 + 4t) + 113
10(t^2 + 4t +4) + 113 - 40
10(t + 2)^2
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Question 45203This question is from textbook College Algebra
: Find the maximum or minimum value of the function
f(t)= 10t^2 + 40t + 113
t = -40/(2*10) = -40/20 = -2 minimum
10(t^2 + 4t) + 113
10(t^2 + 4t +4) + 113 - 40
10(t + 2)^2 + 73
y = 73
Thank you very much again! This question is from textbook College Algebra
You can put this solution on YOUR website! This is correct, except that as long as you found the max/min at , you could have found the minimum value by just substituting this value of t into the original equation:
