You can
put this solution on YOUR website!The profit earned from manufacturing x widgets is
P= .0001x3 - .21x2 + 135x - 2000 ..HOPE YOU KNOW DIFFERENTIATION
DP/DX=0.0001*3X^2-0.21*2X+135=0...FOR P TO HAVE AN EXTREMUM
=0.0003X^2-0.42X+135=0
X=(0.42+ OR - 0.12)/(2*0.0003)
=900 OR 500
D^2P/DX^2=0.0006X-0.42....AT X=900,WE GET...0.0006*900-0.42=0.12....HENCE MINIMUM
AT X=500,WE GET....0.0006*500-0.42=-0.12....HENCE MAXIMUM
SO X=500 IS CORRECT ANSWER...C IS CORRECT
dollars. Other contraints dictate that at least 200 widegets but no more than 950 widgets be manufactured.
How many widgets should be produced to earn the maximum profit?
a. 950
b. 17400
c. 500
d. 25500
e. None of the others
