SOLUTION: The equation h = -16t^2 + 112t gives the height of an arrow, shot upward from the ground with an initial velocity of 112 ft/s, where t is the time after the arrow leaves the ground
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: The equation h = -16t^2 + 112t gives the height of an arrow, shot upward from the ground with an initial velocity of 112 ft/s, where t is the time after the arrow leaves the ground. Find the time it takes for the arrow to reach a height of 180 ft.
This question is from textbook
Answer by Nate(3500) (Show Source): You can put this solution on YOUR website!
h = -16t^2 + 112t
180 = -16t^2 + 112t
0 = -16t^2 + 112t - 180
0 = -4t^2 + 28t - 45
0 = -4(t - 2.5)(t - 4.5)
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