SOLUTION: Find all the real values of x for which the function: f(x) = 18x^3

SOLUTION: Find all the real values of x for which the function: f(x) = 18x^3 - 33x^2 + 20x � 4 becomes zero.

Question 41623: Find all the real values of x for which the function: f(x) = 18x^3 - 33x^2 + 20x � 4 becomes zero.
Answer by psbhowmick(878) (Show Source): You can put this solution on YOUR website!
- 4

By trial we put x = .
We find that .
So, by the Remainder theorem, (2x - 1) must be a factor of f(x).

Now, let us arrrange f(x) in such way that (2x - 1) can be taken as a factor.

=
=
=
=

Hence the function becomes zero when 2x - 1 = 0 i.e. x = or when 3x - 2 = 0 i.e. x = .
RELATED QUESTIONS
find all real zeros of the function... (answered by robertb,jsmallt9)

List all possible rational zeros for the polynomial below. Find all real zeros of the... (answered by lwsshak3)

Use the given zero to find the remaining zeros of the function.... (answered by solver91311)

f(x)=16x squared -20x find all the values for which... (answered by Fombitz)

Use the rational zero theorem to list all possible rational zeros for the given function. (answered by DrBeeee)

Find all the rational zeros of the function f(x)=36x^4+66... (answered by Fombitz,ewatrrr)

find all zeros of the function.... (answered by ewatrrr)

Find all real zeros of the function. {{{ f(x)=x^3+x^2-4x-4... (answered by jim_thompson5910)

Find the real zeros of P(x) = x^4 - x^3 - 18x^2 + 52x - 40. If a zero is a multiple zero, (answered by Nate)