Find a linear function h such that h(-1)=-5 and h(7)=-6. What is h(3/2)?
First you interpret it as this problems:
Find the equation of the line that passes through the two points
(-1,-5) and (7,-6).
Use the slope formula:
y2 - y1 (-6) - (-5) -6 + 5 -1
m = ---------- = -------------- = -------- = ----- =
x2 - x1 7 - (-1) 7 + 1 8
Then use the point-slope formula:
y - y1 = m(x - x1)
y - (-5) = (x - (-1) )
y + 5 = (x + 1)
y + 5 = x -
y = x - - 5
y = x - -
y = x -
Now replace y by h(x)
h(x) = x -
That's the first part.
What is h()?
Substitute for x in
h(x) = x -
h() = -
h() = -
h() = -
h() =
Edwin