SOLUTION: f(x)=5x-4 and g(x)=x^2+3. Find the following:
(g-f)(x)
(fg)(x)
domain of g/f
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Question 410515: f(x)=5x-4 and g(x)=x^2+3. Find the following:
(g-f)(x)
(fg)(x)
domain of g/f
Answer by Theo(13342) (Show Source): You can put this solution on YOUR website!
(g-f)(x)
= g(x) - f(x)
= (x^2 + 3) - (5x - 4)
= x^2 + 3 - 5x + 4
= x^2 - 5x + 7
(fg)(x)
= f(x) * g(x)
= (5x-4) * (x^2 + 3)
= 5x^3 + 15x - 4x^2 - 12
= 5x^3 - 4x^2 + 15x - 12
(g/f)(x)
= g(x) / f(x)
= (x^2 + 3) / (5x-4)
the denominator = 0 when 5x-4 = 0
this occurs when x = 4/5
the function is undefined when the denominator is equal to 0
the domain is therefore all real values of x except when x = 4/5
the graph of this equation looks like this:
if you draw a vertical line at x = 4/5, you will see that the graph of the function approaches that line but never touches it. that means that the line x = 4/5 is an asymptote of the function which also means that that the function is undefined at x = 4/5.
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