SOLUTION: Let(f)=ax^5+bx^3+cx+9 were a,b,and c are constants. If f(6)=17, determine the value of f(-6)

SOLUTION: Let(f)=ax^5+bx^3+cx+9 were a,b,and c are constants. If f(6)=17, determine the value of f(-6)

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Question 407705: Let(f)=ax^5+bx^3+cx+9 were a,b,and c are constants.
If f(6)=17, determine the value of f(-6)
Answer by richard1234(7193) (Show Source): You can put this solution on YOUR website!
Note that all the x exponents (except for the 9) are odd, which means that . Since f(6) = 17, then f(6) - 9 = 8, and

Since the function is odd, then

Adding 9 to obtain the value of f(-6) we get f(-6) = 1.
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