SOLUTION: find the derivative ln x/ square root x^2 +1
y'=?
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Question 405158: find the derivative ln x/ square root x^2 +1
y'=?
Answer by Tatiana_Stebko(1539) (Show Source): You can put this solution on YOUR website!
Use formulas: (u/v)'=(u'v-uv')/v^2
__________'=
__________'='
__________'=, C'=0
'='=('')/=
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