Hi



p(x)=x^2-2x+5 

Using the vertex form of a parabola,  where(h,k) is the vertex

completing the square to put into vertex form

p(x) = (x-1)^2 + 4  vertex Pt(1,4) is a minimum pt, a>0, parabola opens upward

Although the range of p(x) is p(x)>= 4, the domain x-values are all real numbers



 

Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
 Find the domain of the function: 

p(x)=x^2-2x+5 

What is the domain of p?

The domain is the set of Real Number values the variable

"x" can take.

-------------------------------------- 

a) {x|x is a real number}

b) {x|x is a real number and x≠0}

c) {x|x is a real number and x≠5}

d) {x|x is a real number and x>0}

-----------------

Ans: x is unrestricted.

Ans: a

=============

Cheers,

Stan H. 

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