# SOLUTION: For the following problems y varies inversely with the square of x. If y is 4 when x is 5, find y when x is 2.

Algebra ->  Algebra  -> Functions -> SOLUTION: For the following problems y varies inversely with the square of x. If y is 4 when x is 5, find y when x is 2.       Log On

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 Question 35508This question is from textbook : For the following problems y varies inversely with the square of x. If y is 4 when x is 5, find y when x is 2. This question is from textbook Found 3 solutions by Nate, narayaba, Prithwis:Answer by Nate(3500)   (Show Source): You can put this solution on YOUR website!yx^(2)=yx^(2) 4(5^2)=y(2^2) 4(25)=y(4) y=25 Answer by narayaba(40)   (Show Source): You can put this solution on YOUR website!y varies inversely with x^2 y = c*(1/x^2), where c is the proportanality constant y = 4 when x = 5 4 = c*(1/(5*5)) therefore c = 100 y = 100*(1/x^2) when x = 2 then y = 100*(1/(2*2)) = 25 Answer by Prithwis(166)   (Show Source): You can put this solution on YOUR website!y varies inversely with the square of x is equivalent to y = k/x^2 y = k/x^2 Substituing y=4 and x=5: 4 = k/25 => k = 100; Thus, y = 100/x^2 x = 2 => y = 100/2^2 = 100/4 = 25