SOLUTION: Please help me. I tried the only things that I thought would work on this problem and they were wrong. I tried 1 as the solution and 0 because anything else would make the whole th

Question 347654: Please help me. I tried the only things that I thought would work on this problem and they were wrong. I tried 1 as the solution and 0 because anything else would make the whole thing under the sqrt a negative number right. It has me completely stumped.
Let the function f be defined by
f(x) = \sqrt{-7 x + 8}.
Then x is in the domain of f provided x is less than or equal to _____.
Hint: There is no real number that is the square root of a negative real number.

Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
Since the square root argument cannot be negative then,

So the domain is (,]
RELATED QUESTIONS
1/2(x-5)=x/4 I have tried this question so many ways, my head hurts. I can't figure... (answered by ankor@dixie-net.com,solver91311)

Please help me solve this equation: What number is that, 1/5 of which is greater than... (answered by josgarithmetic,solver91311)

For a triangle with a perimeter of 12 and an area of 7 what are the lengths of the... (answered by jim_thompson5910)

Please help me to solve this question: 9 + ? x 3/8 = 15 I tried to work out what ?... (answered by MathTherapy)

I have tried so many different things on this problem, thinking through why they would be (answered by edjones,jim_thompson5910)

Hey :D i attemped this geometry based homework 2 weeks ago, i managed to do questions... (answered by scott8148)

2x^2-1 divided by x^2 were x is equal to 2 how would i work the question? I tried... (answered by josmiceli)

It takes Maria twice as long to complete a certain type of research project as it takes... (answered by oberobic)

can you please help me work out this problem. i need to find the range of this function:... (answered by robertb)