SOLUTION: f(x) = 3x^+2x-4

Algebra.Com
Question 32937: f(x) = 3x^+2x-4
Answer by xcentaur(357)   (Show Source): You can put this solution on YOUR website!
f(x)=3x^+2x-4
equate f(x)=0 to get the roots
now
3x^+2x-4=0
this is a quadratic in x
Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=52 is greater than zero. That means that there are two solutions: .




Quadratic expression can be factored:

Again, the answer is: 0.86851709182133, -1.535183758488. Here's your graph:


So you have your 2 values of x


If you were looking for the domain and range for the function f(x),please post again,clearly stating the question
Hope this helps,
xC

RELATED QUESTIONS

F(x)=3x^2-2x-4 when... (answered by Alan3354)
Given {{{f(x)=2x^2-3x+6}}} Find f(-4) (answered by jim_thompson5910)
Give f(x)= 2x^-3x-3, find f... (answered by Solver92311)
F(x)=3x^2-y^4-2x+3x (answered by richwmiller)
f(x)+3x^2-x+4 find f(2) f(2x)... (answered by solver91311)
f(x)=3x^2-x+4 find f(2) f(2x)... (answered by solver91311)
Given f(x) = 2x^2 - 3x + 4, find the following: f(4) f(-3)... (answered by tutorcecilia)
find x when f(x)=0... (answered by tommyt3rd)
f(x)=2x^4+3x^2-x-12 (answered by ikleyn)