SOLUTION: Please walk me through this problem. I have the answer, but I am unable to work past the second step. a/(a + x) divided by (a + x)/b multiplied by a + x divided by 2ab.
Thank
Algebra.Com
Question 301768: Please walk me through this problem. I have the answer, but I am unable to work past the second step. a/(a + x) divided by (a + x)/b multiplied by a + x divided by 2ab.
Thank you
aesmith2@cox.net
Answer by JBarnum(2146) (Show Source): You can put this solution on YOUR website!
this is what you say the problem is as u have written it
first when u have a fraction over a fraction its a lot easier to calculate if u multiply the top fraction by the reciprical of the bottom fraction.
since a+x is in numerator and there is one a+x in denomerator and they are being multiplied they can be cross cancelled out
multiply the numerators
same thing as befor, when u have a fraction over a fraction its a lot easier to calculate if u multiply the top fraction by the reciprical of the bottom fraction.
cross cancell the ab
multiply across
RELATED QUESTIONS
I am trying to work through the following problem. I have the answer.. but I am trying... (answered by unlockmath)
please show me how to solve a problem similiar to the following so I can solve this one.
(answered by longjonsilver)
I have a problem that I have to evaluate and express the result in scientific notation.
(answered by dkppathak,Theo)
I am sorry but I am trying to help my son figure this out and just don't get it. Below... (answered by bonster)
m/m^2-m-12 + 5/m+3
This is what i came up with but i'm not exactly sure how i... (answered by stanbon)
I am trying to divide a polynomial by a monomial.
Divide: x^2 + 3x - 18 by x - 3... (answered by stanbon)
I have been working on this math problem for awhile now and I got to the second step, but (answered by stanbon)
Please help me answer this question I am stuck and cannot get past it. Thank you for any... (answered by ankor@dixie-net.com)
I am stuck on this problem after I have tried to work it out several different ways, but... (answered by solver91311,ilana)