SOLUTION: can you tell me using this function 4x/x-2 what is the horizontal asymptote? and can you show mwe the work. and with the same one what is the functions y-intercepts I thank you in

Question 290495: can you tell me using this function 4x/x-2 what is the horizontal asymptote? and can you show mwe the work. and with the same one what is the functions y-intercepts I thank you in adv anced .I hope you can help me . a few days a go i asked for help I dont know if it was be cause you had help me before you didnt I hope you do now.
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
4x/(x-2) is not a function.
There is no y, so how can there be a y intercept?
y=4x/(x-2) is a function.
A function is a relationship. You can't have a relationship alone as hard as you try.
There is going to be an asymptote at x=2 because x=2 would make the denominator equal to zero
The y intercept is y when x=0
y=0/-2
so when x=0 y=0
so the y intercept is (0,0) or 0
BTW More than 80% of the questions here get answered.
But not all. It depends on which tutors are available. Problems that are poorly written or missing info or that don't make sense are not usually answered

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