SOLUTION: A movie stunt double jumps from the top of a building 50 ft above the ground onto a pad on the ground below. The stunt double jumps with an initial vertical velocity of 10 ft/secon

Question 281393: A movie stunt double jumps from the top of a building 50 ft above the ground onto a pad on the ground below. The stunt double jumps with an initial vertical velocity of 10 ft/second. Write and graph a function that models the height (in feet) of the stunt double t seconds after she jumps. How long does it take the stunt double to reach the ground.
Answer by Mathematicians(84) (Show Source): You can put this solution on YOUR website!
In order to solve this problem, you need to know a kinematic equation that maps the jump of this stunt double. The general equation is:

Where a is acceleration, t is number of seconds, v is initial velocity and h is initial height.
When you plug in the information you are given, you will have the equation:

I am going to assume this jump takes places on earth and therefore experience gravity with no air resistance, therefore a = -9.8 (works downward), however, we need it in feet as the rest of your units are in feet.
9.8 meters is approximately 32.2 feet
Therefore your new equation is

if we go ahead and multiply 1/2 with -32.2 we get:

This is the equation you need to graph, there are several ways to graph this equation, one being finding the roots and getting a general idea what the graph looks like. The second being completing the square and finding out the vertex and graphing it like that. When you find the roots, you will get two answers, you will see which answer fits the problem the best.
Hopes this helps
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