# SOLUTION: If g(x)=x^2+4x+2 find g(2) and g(x+2) so far I have g(2)= 2^2+4(2)+2 g(2)= 4+8+2 g(2)= 14 g(x+2)= (x+2)^2 + 4(x+2)+2 = x^2 + 4 + 4x + 8 + 2 = x^2 + 4x + 14

Algebra ->  Algebra  -> Functions -> SOLUTION: If g(x)=x^2+4x+2 find g(2) and g(x+2) so far I have g(2)= 2^2+4(2)+2 g(2)= 4+8+2 g(2)= 14 g(x+2)= (x+2)^2 + 4(x+2)+2 = x^2 + 4 + 4x + 8 + 2 = x^2 + 4x + 14       Log On

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 Question 274913: If g(x)=x^2+4x+2 find g(2) and g(x+2) so far I have g(2)= 2^2+4(2)+2 g(2)= 4+8+2 g(2)= 14 g(x+2)= (x+2)^2 + 4(x+2)+2 = x^2 + 4 + 4x + 8 + 2 = x^2 + 4x + 14 I'm not sure if I should replace x with 2 or 14?Answer by JBarnum(2044)   (Show Source): You can put this solution on YOUR website!close but not exact the g(2) is correct 1 mistake with the g(x+2) expand (x+2)^2 add like terms