SOLUTION: Find the vertex of the parabola: f(x)=3x^2-24x+43

Question 269455: Find the vertex of the parabola:
f(x)=3x^2-24x+43
Answer by drk(1908) (Show Source): You can put this solution on YOUR website!
step 1 - factor out the 3 from the first 2 terms to get

step 2 - draw lines after the -8x and the 43. These are number holders. numbers will go here.

step 3 - take 1/2 of the -8 and square it to get (-4)^2. Put this in the parenthesis to get

step 4 - you have put 16 into the (__) information, but there is a 3 on the outside. Multiply 3 by 16 to get 48. We have just added 48 to the right. To keep it all balanced, put -48 in the outside blank space. We get

step 5 - rewrite the trinomial as a binomial squared and simplify the outside numbers as

step 6 state vertex as
(h,k) = (4,-5)
RELATED QUESTIONS
find the equation of the axis of symmetry of the parabola... (answered by jim_thompson5910,stanbon)

Find the vertex and the axis of symmetry for the following graph:... (answered by jim_thompson5910)

Find the exact vertex of the parabola algebraically... f(x) = -3x^2 + 5x + 1 (answered by stanbon)

Find the vertex of the parabola.... (answered by lwsshak3)

find the vertex of the parabola f(x)=... (answered by lwsshak3)

Find the x-coordinate of the vertex of the parabola defined by the function f(x)=... (answered by josgarithmetic,MathTherapy)

Find the vertex of the parabola represented by the equation... (answered by Algebraic)

find the coordinates of the vertex for the parabola f (x) = 3x squared... (answered by solver91311)

find the coordinates of the vertex for the parabola f(x) = 3x squared... (answered by Fombitz)