SOLUTION: How do you solve: 3000=2000(1+.06)^t.

Algebra.Com
Question 22642: How do you solve: 3000=2000(1+.06)^t.
Answer by rapaljer(4671)   (Show Source): You can put this solution on YOUR website!


Divide both sides by 2000:



In order to solve for t, where t is an exponent, you must take the ln of each side of the equation. It also works to take the log of each side--exactly the same answer!


This should bring back the laws of logarithms, in which the exponent becomes the coefficient:


Finally divide both sides by ln(1.06), and calculate with a calculator:
= 6.958515, which rounds off to about 6.96.

R^2 at SCC

RELATED QUESTIONS

How do I solve: 3000=2000(1+.06)^t. I thought that I would try to post my query on this... (answered by stanbon)
how do you solve 1-(1-.06)1/12 (the 1/12) is an... (answered by Fombitz)
how do you solve this problem... (answered by mangopeeler07)
How do you solve: 1/t + 2 = t - 1/t + 7 Thank you! (answered by Fombitz)
How do you solve for t in this equation:... (answered by Alan3354)
Solve for t. 3000(1-e^(-2t))=1,200 So,I know you divide everything by 3000,right? (answered by Alan3354)
how do I find if I deposit $1500 in a savings account that pays 6 percent annual interest (answered by jim_thompson5910)
how do I find if I deposit $1500 in a savings account that pays 6 percent annual interest (answered by josgarithmetic)
how do you solve T=4500+12y... (answered by Alan3354)