SOLUTION: I need help on this word/function problem please.
A meteologist is inflating a spherical balloon with helium gas. If the radius of the balloon is changing at a rate of 1.5 cm per
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Question 225539: I need help on this word/function problem please.
A meteologist is inflating a spherical balloon with helium gas. If the radius of the balloon is changing at a rate of 1.5 cm per second, the function for the radius is r(t)=1.5t. The volume of a sphere is given by the function
V(r)=4/3(pie)r^3. Find (V o r)(t).
Wasn't sure where pie key was.
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
First thing to note: "pie" is a dessert item, generally round in shape with a flaky pastry crust and frequently containing some sort of sweet filling, often made of fruit. "pi" is the English language representation of the lower case Greek alphabetic character used to represent the ratio between the diameter and circumference of a circle.
\ =\ V\left(r(t)\right)\ =\ V(1.5t)\ =\ \frac{4}{3}\pi (1.5t)^3\ =\ \frac{4\cdot3.375}{3}\pi t^3\ =\ \frac{13.5}{3}\pi t^3\ =\ 4.5\pi t^3)
John
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