SOLUTION: find vertex of the parabola y=x^2-8x-5 vertex (?,?)

Question 212980: find vertex of the parabola
y=x^2-8x-5
vertex (?,?)
Answer by drj(1380) (Show Source): You can put this solution on YOUR website!
Find the vertex of the parabola

vertex (?,?)

Let's graph this parabola:

Try this set of x=-2, -1, 0, 1, 2 and substitute into parabola equation.

For example, x=-2, y=(-2)^2-8(-2)-5= 4+16-5=15 point on graph is (-2,15)

One more and then you try, x=0, y=(0)^2-8(0)-5=-5 point on graph is (0,5)

Based on the graph the vertex is (4, -21)

Note when we substitute x=4 in

I hope the above steps were helpful.

For FREE Step-By-Step videos in Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.

Good luck in your studies!

Respectfully,
Dr J

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