SOLUTION: If the domain of x^2+2x=2 is (1,2,3), then what is the range?
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Question 197249This question is from textbook Algebra 1 (cliffsquickreview
: If the domain of x^2+2x=2 is (1,2,3), then what is the range?
This question is from textbook Algebra 1 (cliffsquickreview
Found 2 solutions by solver91311, stanbon:
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
is a quadratic equation. Defining a domain for it doesn't make any sense. The equation has a solution set consisting of two values, neither of which is contained in the stated domain. Now, if what you really meant was:
 = x^2 + 2x - 2)
or
 = x^2 + 2x + 2)
(depending on whether you hit the equals key which is right next to the minus key, or forgot to hold the shift key to type +)
Where the domain is restricted to the set 
Then what you do is substitute each of the values from your domain set into the function and do the arithmetic required to determine the value of the function for that value of the independent variable. With three elements in the domain set, in general you will get either 2 or 3 values for the function -- in this case you will get 3 values. The set consisting of those 3 values is your range.
John
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
If the domain of x^2+2x=2 is (1,2,3), then what is the range?
f(x) = x^2 +2x -2
f(1) = 1 + 2 - 2 = 1
f(2) = 4 + 4 - 2 = 6
f(3) = 9 + 6 - 2 = 13
----------------------
Range = {1,6,13}
=========================
Cheers,
Stan H.
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