SOLUTION: find the coordinates of the vertex y=3x^2

Question 189898: find the coordinates of the vertex
y=3x^2
Found 2 solutions by jim_thompson5910, nerdybill:
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!

In order to find the vertex, we first need to find the x-coordinate of the vertex.

To find the x-coordinate of the vertex, use this formula: .

Start with the given formula.

From , we can see that , , and .

Plug in and .

Multiply 2 and to get .

Divide.

So the x-coordinate of the vertex is . Note: this means that the axis of symmetry is also .

Now that we know the x-coordinate of the vertex, we can use it to find the y-coordinate of the vertex.

Start with the given equation.

Plug in .

Square to get .

Multiply and to get .

So the y-coordinate of the vertex is .

So the vertex is .

Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!

The vertex form of a parabola is:
y= a(x-h)^2+k
where
(h, k) is the vertex
.
In your case, they gave you:
y=3x^2
.
Rewritten in "vertex form" we have"
y=3(x-0)^2 + 0
Therefore, the vertex is at (0,0)

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